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Compute the permutations and combinations. How many three-digit numbers greater than 200 can be formed from the digits 1, 2, 6, 7, and 9, if the digits can be repeated?
A)64
B)100
C)125

Respuesta :

ersi99
for the number to be greater than 200 it should start with 2,6,7 or 9

the answer is B) 100
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MrRoyal

There are 100 three-digit numbers greater than 200 can be formed from the digits

How to determine the number of digits?

The possible digits are given as:

1, 2, 6, 7, and 9

The conditions are:

  • Numbers greater than 200
  • Digits can be repeated

These mean that the first digit can be any of 2, 6, 7, and 9

The other two digits can be any of the 5 digits

So, the number of combination is:

Combination= 4 * 5 * 5

Evaluate

Combination= 100

Hence, there are 100 three-digit numbers greater than 200 can be formed from the digits

Read more about combination at:

https://brainly.com/question/11732255

#SPJ2

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