Respuesta :
Let s be the distance traveled the second day.
1.5s+s=1380
2.5s=1380
s=552
So on the first day he traveled 1380-552=828 miles.
1.5s+s=1380
2.5s=1380
s=552
So on the first day he traveled 1380-552=828 miles.
Answer:
A
Step-by-step explanation:
Let distance travelled on first day be [tex]f[/tex] and distance travelled on second day be [tex]s[/tex], so we can write:
[tex]f+s=1380[/tex] [since in 2 days he travelled a total of 1380 miles]
Also, since first day he travelled 1.5 times second day, we can write:
[tex]f=1.5s[/tex]
Substituting this into first equation and solving for [tex]s[/tex], we get:
[tex]1.5s+s=1380\\2.5s=1380\\s=\frac{1380}{2.5}=552[/tex]
We want to know how many miles he drove on first day, which is 1.5 times this, so we have:
[tex]FirstDay=1.5(552)=828[/tex] miles
Answer choice A is correct.