Respuesta :
formula for compound interest is P(1+(r/n))^nt
P=principle (5000)
r=rate (4% or 0.04)
n= number of times compounded (semi annually 2 times)
t= time (3 years)
$8130.81 after the 2500 deposit
at the end of the fifth year $8459.29
P=principle (5000)
r=rate (4% or 0.04)
n= number of times compounded (semi annually 2 times)
t= time (3 years)
$8130.81 after the 2500 deposit
at the end of the fifth year $8459.29
Answer:
$8,801.05
Step-by-step explanation:
Lisa Richter deposited $5,000 at 4% compounded semiannually for three years.
To calculate the amount after 3 years we use the formula
[tex]A=P(1+\frac{r}{n})^{nt}[/tex]
Where A = Future amount
P = Principal amount ($5,000)
r = rate of interest 4% (0.04)
n = number of compounding interest semiannually (2)
t = time (3 years)
Now put the values in the formula
[tex]A=5000(1+\frac{0.04}{2})^{(2)(3)}[/tex]
[tex]A=5000(1+0.02)^{(2)(3)}[/tex]
[tex]A=5000(1.02)^{(6)}[/tex]
A = 5000(1.126)
A = $5,630.81
At the beginning of the fourth year Lisa deposited $2,500. Now the amount would be
New principal amount = 5630.81 + 2500 = 8,130.81
we have to calculate the future amount at the end of five years or for 2 more years.
We will use the same method as we done above.
[tex]A=8130.81(1+\frac{0.04}{2})^{(2)(2)}[/tex]
[tex]A=8130.81(1+0.02)^{(4)}[/tex]
[tex]A=8130.81(1.02)^{(4)}[/tex]
A = 8130.81 (1.08243)
A = $8,801.05
Lisa's balance at the end of five years $8,801.05