What is the probability that a point chosen at random in the given figure will be inside the larger triangle and outside the smaller triangle?

Enter your answer, as a fraction in simplest form, in the box.
P(inside larger triangle and outside smaller triangle) =

Given:
Area of a triangle = (h*b) / 2

Area of smaller triangle = (4cm * 4cm) / 2 = 16cm² / 2 = 8 cm²
Area of larger triangle = (6cm * 10cm) / 2 = 60cm² / 2 = 30 cm²

30cm² - 8cm² = 22cm²

Probability that the point is inside the large triangle but outside the small triangle:

22cm² / 30cm² → 11/15 → 0.73 or 73%

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ayhuhka ayhuhka · Answer 2 · 2019-06-10T22:27:09+02:00

ayhuhka ayhuhka

10-06-2019

Answer: 22cm² / 30cm² → 11/15 → 0.73 or 73%

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What is the probability that a point chosen at random in the given figure will be inside the larger triangle and outside the smaller triangle? Enter your answer, as a fraction in simplest form, in the box. P(inside larger triangle and outside smaller triangle) =

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What is the probability that a point chosen at random in the given figure will be inside the larger triangle and outside the smaller triangle?

Enter your answer, as a fraction in simplest form, in the box.
P(inside larger triangle and outside smaller triangle) =