Respuesta :
If you are given midpoints R, S, T of AB, BC and CA then you will have a line like this
A----B----C
A--R--S--T--C
then if you have are given line RS = 5, ST, TC and AR are also 5 since they are midpoints of the line and thus you will have a whole length of 20.
A----B----C
A--R--S--T--C
then if you have are given line RS = 5, ST, TC and AR are also 5 since they are midpoints of the line and thus you will have a whole length of 20.
Answer:
AC= 10
Step-by-step explanation:
Given: In ΔABC , R,S,T are the midpoints of AB, BC and CA
length of RS= 5
To find : length of AC
Solution: By mid segment theorem which state that
In a triangle, the segment joining the midpoints of any two sides will be parallel to the third side and half of its length.
using this theorem , RS parallel to AC and
[tex]RS= \frac{1}{2} AC[/tex]
[tex]5= \frac{1}{2} AC[/tex]
[tex]AC= 10[/tex]