Answer: The probability that the card is a football card or a basketball card is [tex]\frac{35}{50}[/tex].
The probability that the sum of the numbers on the number cubes is either a multiple of 3 or an odd number is [tex]\frac{2}{3}[/tex]
Step-by-step explanation:
Let A be the event of getting a football card and b be the event of getting a basketball card.
Thus probability of getting a foot ball P(A)= [tex]\frac{20}{50}[/tex]
The probability of getting a basketball P(B)= [tex]\frac{15}{50}[/tex]
Selecting a card is a mutually exclusive event , thus probability of getting card is a football card or a basketball card P(A∩B) =P(A)+P(B)
⇒P(A∪B[tex]=\frac{20}{50}+\frac{15}{50}=\frac{35}{50}[/tex]
The probability that the card is a football card or a basketball card is [tex]\frac{35}{50}[/tex].
Let E be the event of getting a multiple of 3 and F be the event of getting an odd number.
Then P(A)=[tex]\frac{2}{6}[/tex]
P(B)=[tex]\frac{3}{6}[/tex]
P(A∩B)=[tex]\frac{1}{6}[/tex] [3 is both a multiple of 3 and an odd number]
Thus, P(A∪B)=P(A)+P(B)-P(A∩B)
⇒P(A∪B)[tex]=\frac{4}{6}=\frac{2}{3}[/tex]
The probability that the sum of the numbers on the number cubes is either a multiple of 3 or an odd number is [tex]\frac{2}{3}[/tex]
