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HELP ASAP!!!!!!!!
The probability of a randomly selected employee of a company being male is 60%. The probability of the employee being less than 30 years old is 70%. If the probability of the employee being less than 30 years old given that the employee is a male is 40%, what is the probability that the employee is a male, given that the employee is less than 30 years old?
A. 0.34
B. 0.42
C. 0.55
D. 0.69
E. 0.71

Respuesta :

Answer:

The correct answer is A. 0.34

Step-by-step explanation:

Let the event male is donated by M and the event that age is less than 30 is denoted by L

Now, P(M) = 60% = 0.6

P(L) = 70% = 0.7

P(L/M) = 40% = 0.4

[tex]\text{Conditional probability, P(L/M) is given by : }\frac{P(L\:\:and\:\:M)}{P(M)}\\\\\implies P(L\:\:and\:\:M)=0.4\times P(M)\\\\\implies P(L\:\:and\:\:M) = 0.4\times 0.6\\\\\implies P(L\:\:and\:\:M) =0.24[/tex]

Now, we need to calculate P(M/L)

[tex]\implies P(M/L)=\frac{P(L\:\:and\:\:M)}{P(L)}\\\\\implies P(M/L)=\frac{0.24}{0.7}\\\\ \implies P(M/L) =0.3429\approx 0.34[/tex]

Therefore, The correct answer is A. 0.34

arnavkondhare16

Answer:

A. 0.34

Step-by-step explanation:

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