Respuesta :
Answer:
x = 35°
Step-by-step explanation:
Given : [tex]\sin 55^{\circ}=\cos x[/tex]
We have to solve for x.
Consider
[tex]\sin 55^{\circ}=\cos x[/tex]
We know the relation,
[tex]\sin (90^{\circ}-\theta)=\cos \theta[/tex] .....(1)
also [tex]\sin 55^{\circ}[/tex] can be written as
[tex]\sin 55^{\circ}=\sin(90^{\circ}-35^{\circ})[/tex] .....(2)
Comparing the two equations (1) and (2) , we have,
[tex]\sin (90^{\circ}-35^{\circ})=\cos 35^{\circ}[/tex]
Thus, x = 35°
The value of x missing in the box is; x = 35°
Trigonometry
We know that if an angle is x, in trigonometry, we say that;
sin x = cos (90 - x)
Thus;
sin 55 = cos (90 - 55)
sin 55 = cos 35
In conclusion, the missing value as x in the question was gotten to be 35°
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