A funnel is shaped approximately like a cone. The diameter of the base is 6 inches. The height is 10 inches. What is the approximate volume of the funnel? Use 3.14 for pi, and round to the nearest tenth. a. 94.2 in.3 c. 226.1 in.3 b. 18.8 in.3 d. 28.3 in.3

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Aut0
The answer is A. 94.2
V=π*r^2*h/3 is your formula

Answer: A.  [tex]94.2\text{ inches}^3[/tex]

Step-by-step explanation:

The volume of cone is given by :-

[tex]V=\dfrac{1}{3}\pi r^2 h[/tex], where r is radius and h is height of the cone.

Given: Diameter of base: 6 inches

Then Radius =[tex]\dfrac{6}{2}=3\text{ inches}[/tex]

Height : 10 inches

Then , the volume of the cone will be :-

[tex]V=\dfrac{1}{3}(3.14) (3)^2 (10)=94.2\text{ inches}^3[/tex]

Hence, the volume of the cone = [tex]94.2\text{ inches}^3[/tex]