Respuesta :
h=5 days
A0=200.0 g
t=15 days
A=?
A=A0 (1/2)^t/h
= 200.0 g (1/2)^15/5
=25 g remains
A0=200.0 g
t=15 days
A=?
A=A0 (1/2)^t/h
= 200.0 g (1/2)^15/5
=25 g remains
After 15 days, 25 grams of the radioisotope will remain left.
According to the question,
Half life of the radioisotope,
- 5 days.
Throughout the 15 days the radioisotope is halved 3 times,
- [tex]\frac{15 \ days}{5 \ days}[/tex]
Now,
→ The amount of isotope that will:
= [tex]200\times \frac{1}{2}\times \frac{1}{2}\times \frac{1}{2}[/tex]
= [tex]200\times \frac{1}{8}[/tex]
= [tex]25 \ g[/tex]
Thus the above response is correct.
Learn more about radioisotope here:
https://brainly.com/question/9673970