Respuesta :

h=5 days
A0=200.0 g
t=15 days
A=?

A=A0 (1/2)^t/h
  
  = 200.0 g (1/2)^15/5
  =25 g remains

After 15 days, 25 grams of the radioisotope will remain left.

According to the question,

Half life of the radioisotope,

  • 5 days.

Throughout the 15 days the radioisotope is halved 3 times,

  • [tex]\frac{15 \ days}{5 \ days}[/tex]

Now,

→ The amount of isotope that will:

= [tex]200\times \frac{1}{2}\times \frac{1}{2}\times \frac{1}{2}[/tex]

= [tex]200\times \frac{1}{8}[/tex]

= [tex]25 \ g[/tex]

Thus the above response is correct.

Learn more about radioisotope here:

https://brainly.com/question/9673970