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For example, at sea level the atmospheric pressure is 760 mm Hg (also expressed as 760 torr, 101325 Pa, 101.3 kPa, 1013.25 mbar or 14.696 psi) and pure water boils at 100°C. However, in Calgary (approx. 1050m above sea level) the atmospheric pressure is approximately 670 mm Hg, and water boils at about 96.6°C.

The boiling point of water at 620 mm Hg has been calculated as 93.7 [tex]\rm \bold{^\circ C}[/tex].

The boiling point can be defined as the temperature at which the liquid state has been converted to the gaseous state. The boiling point of water at 760 mm Hg has been 100 [tex]\rm ^\circ C[/tex].

The boiling point of water at pressure can be given by:

Boiling point at sea level = Unknown temperature - (Given pressure - Pressure at sea level ) [tex]\rm \times\;0.045\;^\circ C/mm Hg[/tex]

100 [tex]\rm ^\circ C[/tex] = Unknown BP - (620 mm Hg - 760 mm Hg ) [tex]\rm \times\;0.045\;^\circ C/mm Hg[/tex]

100 [tex]\rm ^\circ C[/tex] = Unknown BP -  (-140 mm Hg)  [tex]\rm \times\;0.045\;^\circ C/mm Hg[/tex]

100 [tex]\rm ^\circ C[/tex] =  Unknown BP + 6.3

Unknown boiling point = 100 - 6.3

Unknown boiling point = 93.7 [tex]\rm \bold{^\circ C}[/tex].

The boiling point of water at 620 mm Hg has been calculated as 93.7 [tex]\rm \bold{^\circ C}[/tex].

For more information about the boiling point, refer to the link:

https://brainly.com/question/2153588