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What are the approximate solutions of 4x2 + 2x = 17, rounded to the nearest hundredth?

x ≈ −2.33 and x ≈ 1.83
x ≈ −1.83 and x ≈ 2.33
x ≈ −9.31 and x ≈ 7.31
No real solutions

Respuesta :

viskadriskav
Use the quadratic formula to solve. -2 +\- √(2)^2 - 4(4)(-17) / 2(4). Simplify to -2 +\- √276/8. √276 is about 16.61. Now, do -2 +16.61/8 which is 1.83, and -2 -16.61/8 which is -2.33. A is your solution
isyllus

Answer:

The solutions are -2.33 and 1.83

A is correct.

Step-by-step explanation:

Given: [tex]4x^2+2x=17[/tex]

First we make quadratic equation and then use quadratic formula.

[tex]4x^2+2x=17[/tex]

Subtract 17 both sides

[tex]4x^2+2x-17=0[/tex]

Quadratic formula:

[tex]x=\dfrac{-b\pm \sqrt{b^2-4ac}}{2a}[/tex]

where, a=4 , b=2 , c=-17

[tex]x=\dfrac{-2\pm \sqrt{2^2-4(4)(-17)}}{2(4)}[/tex]

[tex]x=\dfrac{-2\pm \sqrt{276}}{8}[/tex]

[tex]x=\dfrac{-2\pm 16.61}{8}[/tex]

[tex]x=-2.33\text{ or }1.83[/tex]

Hence, The solutions are -2.33 and 1.83

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