[tex]\bf 2\sqrt{50}-3\sqrt{32}\qquad
\begin{cases}
50\to \cdot 2\cdot 5\cdot 5\\
\qquad 2\cdot 5^2\\
32\to 2\cdot 2\cdot 2\cdot 2\cdot 2\\
\qquad 2^2\cdot 2^2\cdot 2\\
\qquad (2^2)^2\cdot 2\\
\qquad 4^2\cdot 2
\end{cases}\implies 2\sqrt{2\cdot 5^2}-3\sqrt{4^2\cdot 2}
\\\\\\
2\cdot 5\sqrt{2}-3\cdot 4\sqrt{2}\implies 10\sqrt{2}-12\sqrt{2}\implies (10-12)\sqrt{2}\implies \boxed{-2\sqrt{2}}[/tex]
