Respuesta :
First add one to both sides to make the left side 0. This makes the a value 5 theb value -2 and the c value 1. The discriminant is b squared -4ac. Plug it in to get (-2)^2-4(5). 4-10=-6. The resulting number is less than zero so there are no real number solutions.
Answer:
discriminant of the quadratic equation is -16, The resulting number is less than zero so there are no real number solutions.
Step-by-step explanation:
Given : he quadratic equation −1 = 5x² −2x.
To find : What is the value of the discriminant .
Solution : We have given that −1 = 5x² −2x.
−1 = 5x² −2x.
On adding by 1 both sides
0 = 5x² −2x +1
On switching sides
5x² −2x +1 = 0
Compare it standard form of quadratic equation ax² +bx +c = 0.
Here, a = 5, b= -2, c = 1
By Discriminant formula:
D = [tex]b^{2} -4ac[/tex]
Substituting the values
D = [tex](-2)^{2} -4(5)(1)[/tex].
D = 4 - 20
D = -16.
Therefore, discriminant of the quadratic equation is -16, The resulting number is less than zero so there are no real number solutions.