Triangle ABO is a right-angled triangle If AO = 32 and BC = 98, then the length of AB would be 126 unit.
What is Pythagoras' Theorem?
If ABC is a triangle with AC as the hypotenuse and angle B with 90 degrees then we have:
|AC|^2 = |AB|^2 + |BC|^2
where |AB| = length of line segment AB. (AB and BC are rest of the two sides of that triangle ABC, AC being the hypotenuse).
The given information is AB is tangent to O. If AO = 32 and BC = 98,
Triangle ABO is a right-angled triangle
AO=CO
two congruent radii
where
AO=32
BO = BC + CO
= 98 + 32
= 130
By using Pythagoras' theorem
[tex]|BO|^2 = |AB|^2 + |AO|^2\\ \\ |130|^2 = |AB|^2 + |32|^2 \\\\16900 = |AB|^2 + 1024\\\\AB = \sqrt{15976} \\\\AB = 126 . 39[/tex]
Learn more about Pythagoras' theorem here:
https://brainly.com/question/12105522
#SPJ2
