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A sample of a compound contains 60.0 g C and 5.05 g H. Its molar mass is 78.12 g/mol. What is the compound’s molecular formula

Respuesta :

The standard atomic weight of a C is 12, and the standard atomic weight of a H is 1.  So to find molar ratio of C and H in the compound: 60.0/12=5, 5.05/1=5. This means the molar ratio of C and H is 5:5, thus 1:1.  Assuming the molecular formula is CnHn, to find molar mass: 12n + 1n = 78.12.  n=78.12/(12+1) = 6.  So the compound's molecular formula is C6H6, benzene.
samueladesida43

The molecular formula of the compound that contains 60.0 g C and 5.05 g H with a molar mass of 78.12 g/mol is C6H6.

How to calculate molecular formula?

The molecular formula of a compound can be calculated from the empirical formula, which can be found as follows:

First, we convert mass of each element to moles:

  • C = 60g ÷ 12g/mol = 5mol
  • H = 5.05g ÷ 1g/mol = 5.05mol

Next, we divide each mole by the smallest:

  • C = 5mol ÷ 5 = 1
  • H = 5.05mol ÷ 5 = 1.01

The empirical ratio of C and H is 1:1, hence, the empirical formula is 1:1.

(CH)n = 78.12

(13)n = 78.12

n = 78.12/13

n = 6

Therefore, the molecular formula of the compound that contains 60.0 g C and 5.05 g H with a molar mass of 78.12 g/mol is C6H6.

Learn more about molecular formula at: https://brainly.com/question/14425592

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