Respuesta :
Solution of the given quadratic equation [tex]2x^{2} -2x -9=0[/tex] is equals to
( 1±√19) / 2.
What is quadratic equation?
" Quadratic equation is an algebraic expression of the given polynomial consisting variable with highest degree two. General representation of the quadratic equation is [tex]ax^{2} +b x +c=0[/tex] where a ≠ 0 ."
Formula used
[tex]D=\frac{b^{2} -4ac}{2a}[/tex]
D > 0 , Roots are real and distinct.
x = (-b ± √D) /2a
According to the question,
Given quadratic equation,
[tex]2x^{2} -2x-9=0[/tex]
Here,
a = 2
b= -2
c= -9
Substitute the value in the given formula of quadratic equation we get,
D = (-2)² - 4(2)(-9)
= 4+72
= 76 >0
D>0, Roots are real and distinct of the given quadratic equation.
x = [-(-2) ± √(-2)² -4(2)(-9)] / 2(2)
= (2 ±√76) / 4
= (1±√19) / 2
Hence, the solutions of the given quadratic equation [tex]2x^{2} -2x -9=0[/tex] is equals to ( 1±√19) / 2.
Learn more about quadratic equation here
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