A. increases
Explanation:
We can answer the question by reminding Kepler's third law, which states that
"for an object in motion around a central object (such as a satellite in orbit around a planet), the cube of the distance between the satellite and the centre of the orbit is proportional to the square of its orbital period"
In formula, this can be written as
[tex]\frac{r^3}{T^2}=const.[/tex]
where r is the distance between the satellite and the central object while T is the orbital period of the satellite. From this relationship, we see that if r (the distance) increases, then the period of the satellite (T) increases as well.
