In the parallelogram shown, AE = p − 8, CE = 2p − 58, and DE = p + 15. What is the length of line segment EB?

42 units
50 units
65 units
73 units

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helperjoe helperjoe · Answer 1 · 2017-05-25T17:44:37+02:00

DE = EB

DE = p + 15

I would help you farther but I don't know what p equals. If you know then add that number with 15 and you have your answer.

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carlosego carlosego · Answer 2 · 2018-08-21T23:59:33+02:00

The first thing we must do is find the value of p.

For this, we use the following equality:

[tex] AE = EC
[/tex]

Substituting values we have:

[tex] p - 8 = 2p - 58
[/tex]

Clearing the value of p we have:

[tex] 2p - p = 58 - 8

p = 50
[/tex]

Then, we look for the length of EB.

We know that:

[tex] EB = DE
[/tex]

Substituting values we have:

[tex] EB = p + 15

EB = 50 + 15

EB = 65
[/tex]

Answer:

the length of line segment EB is:

65 units