Respuesta :
Probability of a fish eat worms given that it eats shrimp
[tex]P(w|s)= \frac{P(w∩s}{P(s)} [/tex]
[tex]P(w|s)= \frac{0.2}{0.6} [/tex]
[tex]P(w|s)= \frac{1}{3} [/tex]
[tex]P(w|s)= \frac{P(w∩s}{P(s)} [/tex]
[tex]P(w|s)= \frac{0.2}{0.6} [/tex]
[tex]P(w|s)= \frac{1}{3} [/tex]
Answer: [tex]\dfrac{1}{3}[/tex]
Step-by-step explanation:
Given: The probability that a fish eats shrimp only =[tex]P(S-W)=0.4[/tex]
The probability that a fish eats shrimp and worms =[tex] P(W\cap S)=0.2[/tex]
Now, the probability that a fish eats shrimp =[tex]P(S-W)+P(S\cap W)=0.4+0.2=0.6[/tex]
The probability that a fish eats worms, given that it eats shrimp is given by:-
[tex]P(W|S)=\frac{P(W\cap S)}{P(S)}\\\\=\frac{0.2}{0.6}\\\\=\frac{1}{3}[/tex]
The probability that a fish eats worms, given that it eats shrimp= [tex]\dfrac{1}{3}[/tex]