The height of the triangular base of the pyramid is; h = (5/2)√3 units
What is the height of the pyramid base?
The height of the equilateral triangle base of the pyramid divides the equilateral triangle into two equal parts as shown in the image. And it also dimensions the bottom side into two equal parts of 5/2 units each.
Let this height be called h.
Using Pythagoras theorem, we have;
5² = h² + (5/2)²
5² = h² + (5²/4)
h² = 5² - (5²/4)
h² = 75/4
h = √(75/4)
h = (5/2)√3 units
Read more about pyramid height at; https://brainly.com/question/22744289
