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An arena is hosting a rock concert. It has “silver” and “gold” seating sections. The event organizers are selling the first 100 gold tickets at the price of a silver ticket. The price of a silver ticket is $7 more than 1/2 the price of a gold ticket. The price of a silver ticket is $14 less than 6/5 the price of a gold ticket. How much will one of the first 100 buyers save on the price of a gold ticket?

Respuesta :

mathmate

Let G=cost of gold ticket.


Silver ticket costs

S=G/2+7, and

S=6G/5-14


Equate both,

6G/5-14=G/2+7

simplify

6G/5-G/2 = 7+14

12G/10-5G/10=21

7G/10=21

Cross multiply

G=10*21/7=30 => Gold tickets cost $30 each.


S=G/2+7=30/2+7=15+7=22

Silver tickets cost $22 each.


The first 100 gold ticket purchasers will therefore save $30-$22=$8 each ticket.

Answer:

$8

Step-by-step explanation:

Let G=cost of gold ticket.

Silver ticket costs

S=G/2+7, and

S=6G/5-14

Equate both,

6G/5-14=G/2+7

simplify

6G/5-G/2 = 7+14

12G/10-5G/10=21

7G/10=21

Cross multiply

G=10*21/7=30 => Gold tickets cost $30 each.

S=G/2+7=30/2+7=15+7=22

Silver tickets cost $22 each.

The first 100 gold ticket purchasers will therefore save $30-$22=$8 each ticket.Let G=cost of gold ticket.

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