we have
[tex]-4\leq 3x-1[/tex] ----> inequality A
[tex]-4\leq 3x-1 \\-4+1 \leq 3x\\-3 \leq 3x\\-1\leq x\\ x\geq-1[/tex]
The solution of the inequality A is the interval ------> [-1,∞)
[tex]2x+4\leq 18[/tex] -------> inequality B
[tex]2x \leq 18-4[/tex]
[tex]x \leq 14/2[/tex]
[tex]x \leq 7[/tex]
The solution of the inequality B is the interval ------> (-∞,7]
The solution of the compound inequality is
[-1,∞) ∩ (-∞,7]=[-1,7]
therefore
the answer in the attached figure
