emersonl emersonl

25-05-2017
Chemistry

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I am unsure how to do this, definitely need some help.

I am unsure how to do this definitely need some help class=

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Fatty12 Fatty12

25-05-2017

It would be c +170kj

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BeUrAwesomeSelf BeUrAwesomeSelf

25-05-2017

(c) is the answer. Sorry for the delay, enjoy your day!

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