Answer:
[tex]\frac{7}{8}[/tex]
Step-by-step explanation:
We are given that three dice rolled.
Even number in a dice =3
Odd numbers in a dice =3
Total number of cases in a dice=6
Probability =[tex]\frac{number\;of\;favorable\;cases}{total\;number\;of\;cases}[/tex]
Probability of getting an odd number when a dice rolled =[tex]\frac{3}{6}=\frac{1}{2}[/tex]
Probability that three dice show odd number when three dice rolled=[tex](\frac{1}{2})^3=\frac{1}{8}[/tex]
Therefore, the probability that at-least one of the dice will show an even number=[tex]1-\frac{1}{8}=\frac{7}{8}[/tex]
Answer:[tex]\frac{7}{8}[/tex]
