Given: <SUR ≡ <TVR and SU≡TV
Prove Δ SUR ≡ Δ TVR.
Consider Δ SUR and ΔTVR:
a) SU≡TV (given)
b) <SUR ≡ <TVR (given)
c) <SRU ≡ <TRV (Vertical angle or opposite angle)
d) Then we have 2 angles and one side Δ SUR that are congruent to same in the corresponding ΔTVR===> Theorem
" If two angles and the non-included side of one triangle are congruent to the corresponding parts of another triangle, the triangles are congruent."
Hence both triangle are congruent AAS, as per the above theorem
