Respuesta :
x^3 - 14x^2 + 49x = 0
Factor an x out:
x(x^2 - 14x + 49) = 0
Find two factors of 49 that add to -14 (-7 and -7). Convert the trinomial to two binomials:
x(x - 7)(x - 7) = 0
The zeros are:
x = 0 and x = 7.
7 occurs as a zero twice and therefore has a multiplicity of 2.
Factor an x out:
x(x^2 - 14x + 49) = 0
Find two factors of 49 that add to -14 (-7 and -7). Convert the trinomial to two binomials:
x(x - 7)(x - 7) = 0
The zeros are:
x = 0 and x = 7.
7 occurs as a zero twice and therefore has a multiplicity of 2.
The zero of the equation is 0, 7 and 7 has multiplicity of 2, the correct answer is B.
What is a zero of an equation?
The point at which the value of the equation becomes zero is called the zero of an equation.
The equation is f(x) = x³ -14x²+49x
x ( x² -14x +49) = 0
x ( x² - 7x -7x +49 ) = 0
x ( x -7)² = 0
x = 0 , 7
7 has multiplicity of 2.
Therefore, the zero of the equation is 0, 7 and 7 has multiplicity of 2, the correct answer is B.
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