An ideal gas occupies a volume of 0.60 m3 at 5.0 atm and 400. K. What volume does it occupy at 4.0 atm and a temperature of 200. K?

Respuesta :

V1 = 0.60 m3, P1 = 5.00atm, T1=400K
V2 = ??m3, P2 = 4.00atm, T2=200K
P1V1/T1 = P2V2/T2
V2 = T2P1V1/T1P2 = 200×5×0.60/400×4.00 = 600/1600
V2 = 0.38 m3

The volume is  0.38 m³.

How to find Ideal gas volume?

To find ideal gas volume:

Combined gas law: P1V1/T1 = P2V2/T2 Use the gas laws for pressure, volume, and temperature calculations.

V1 = 0.60 m3, P1 = 5.00atm, T1=400K

V2 = ??m3, P2 = 4.00atm, T2=200K

P1V1/T1 = P2V2/T2

V2 = T2P1V1/T1P2 = 200×5×0.60/400×4.00 = 600/1600

V2 = 0.38 m3

What is Ideal Gas?

Many gases along with nitrogen, oxygen, hydrogen, noble gases, a few heavier gases like carbon dioxide, and combinations such as air, can be treated as the best gases within affordable tolerances over a widespread parameter variety around standard temperature and stress.

Learn more about Ideal Gas here: brainly.com/question/20212888

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