A boat travels 8 miles north from point A to point B. Then it moves in the direction S 40º W and reaches point C. Finally, it turns S 40º E and returns to point A. The total distance covered by the boat is miles.

Respuesta :

The total distance covered by the boat is 18.44 miles.

Answer:

The distance covered by boat is 18.44 miles.

Step-by-step explanation:

Use the given information to draw a figure.

[tex]\angle B=\angle BCN=40^{\circ}[/tex]            (Alternate interior angles)

[tex]\angle BCN+\angle BCA+\angle ACS=180^{\circ}[/tex]     (Supplementary angles)

[tex]40^{\circ}+\angle BCA+40^{\circ}=180^{\circ}[/tex]

[tex]\angle BCA=100^{\circ}[/tex]

According to angle sum property of a triangle, the sum of interior angles is 180 degree.

[tex]\angle A+\angle B+\angle BCA=180^{\circ}[/tex]

[tex]40^{\circ}+\angle B+100^{\circ}=180^{\circ}[/tex]

[tex]\angle B=40^{\circ}[/tex]

Since two angles are same, therefore ABC is isosceles triangle.

[tex]BC=AC[/tex]

Use Law of Sine:

[tex]\frac{a}{\sin A}=\frac{b}{\sin B}=\frac{c}{\sin C}[/tex]

[tex]\frac{BC}{\sin A}=\frac{AC}{\sin C}[/tex]

[tex]\frac{BC}{\sin 40}=\frac{8}{\sin 100}[/tex]

[tex]BC=\frac{8}{\sin 100}\times \sin 40=5.22[/tex]

[tex]BC=AC=5.22[/tex]

The perimeter of triangle ABC is

[tex]AB+BC+CA=8+5.22+5.22=18.44[/tex]

Therefore the distance covered by boat is 18.44 miles.

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