logderivative logderivative

22-04-2015
Mathematics

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find the derivative sinxln5x

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belcatya belcatya

22-04-2015

sinxln5x=(sinx)'*ln5x+sinx*(ln5x)'=cosx*ln5x+sinx*[tex] \frac{1}{x} [/tex]=cosx*ln5x+[tex] \frac{sinx}{x} [/tex]

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