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The length of a rectangle is 5 inches more than the width. The perimeter is 38 inches. Find the length and the width.

Respuesta :

The formula for perimeter is P=2L+2W (L is length and W is width).

If the length is 5 inches more than the width, that means L=W+5

Now we can just plug that into the formula, so that gives us P=2(W+5)+2W

Simplify that, which equals P=2W+10+2W

Combine like terms: P=4W+10

Since we know the perimeter, let's plug n 38 as P

Now we have 38=4W+10

Subtract 10, giving you 28=4W

Now divide by 4, you get 7=W

So the length is 12 inches and the width is 7 inches

The length and the width of the rectangle is 12 and 7 inches repectively.

What is perimeter?

The perimeter of a shape is defined as the total length of its boundary.

What is the formual for the perimeter of rectangle?

The formula for the perimeter of the recatngle is

Perimeter = 2( length + width)

Let the width of the rectangle be w.

According to the given question.

The perimeter of the recatngle is 38 inches.

The length of the rectangle is 5 inches more than the width.

⇒ length of the recatngle = 5 + w

Now,

The perimeter of the rectangle = 2(length + width)

⇒ 38 = 2 ( 5 + w+ w)

[tex]\implies \frac{38}{2} = 2(5 + 2w)[/tex]

[tex]\implies 19 = 5 + 2w\\\implies 19-5 = 2w\\\implies 14 = 2w\\\implies w = \frac{14}{2} \\\implies w = 7[/tex]

Therefore,

Length of the rectangle = 7 + 5 = 12 inches.

Hence, the length and the width of the rectangle is 12 and 7 inches repectively.

Find out more information about the perimeter of the recatngle here:

https://brainly.com/question/14689998

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