Answer:
Option B.
Step-by-step explanation:
The given polynomial is
[tex]3x^3+x=2x^2+1[/tex]
Equate LHS and RHS equal to y, to get the system of equations.
The system of equations is
[tex]y=3x^3+x[/tex]
[tex]y=2x^2+1[/tex]
The given polynomial can be written as
[tex]P(x)=3x^3+x-2x^2-1[/tex]
Using graphing tool draw the graph of polynomial and system of equations.
From the below graph it is clear that the graph of polynomial intersect the x-axis once at (0.784,0). So, the equation has one zero.
The graph of system of equations intersect each other at one point (0.784,2.229). So, the system has one solution.
The y coordinates of the solutions to the system and the zeroes of the equation are not equal.
Therefore, the correct option is B.
the y coordinates of the solutions to the system and the zeroes of the equation are not equal.
Given
The given polynomial is;
[tex]\rm 3x^3+x=2x^2+1[/tex]
An expression of more than two algebraic terms, especially the sum of several terms that contain different powers of the same variable(s).
The sum of or difference between two polynomials may not necessarily be a polynomial.
This is so because the addition or subtraction of the polynomials may yield a function other than a polynomial.
Therefore,
The equation can be written as;
[tex]\rm 3x^3+x=2x^2+1\\\\\rm 3x^3+x-2x^2-2=0\\\\[/tex]
Hence, the y coordinates of the solutions to the system and the zeroes of the equation are not equal.
To know more about Polynomial click the link given below.
https://brainly.com/question/17822016
