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What is the equation of the line with a slope of (3,4) that goes through the point (4,1) in slope/intercept form?

Respuesta :

Ya2345
4-1= 3
3-4= -1     slope= -3

y-4=-3(x-3)
y-4=-3x+9
y=-3x +13
CharlieBrown2002

Hi there! :)

Step-by-step explanation:

[tex]slope=\frac{Y_2-Y_1}{X_2-X_1}=\frac{RISE}{RUN}[/tex]

[tex]\frac{1-4}{4-3}=\frac{-3}{1}=-3[/tex]

Slope is -3.

Slope-intercept form: [tex]y=mx+b[/tex]

m: represents the slope.

b: represents the y-intercept.

[tex]y-4=-3(x-3)[/tex]

[tex]y-4=-3x+9[/tex]

[tex]y=-3x+13[/tex]

Final answer is y=-3x+13

Hope this helps!

:)

:D

Have a nice day! :)

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