1. The measures of the length and the width of the picture are equal, so the picture is square shaped.
2. The enlarged picture will still be a square, since when we enlarge, we enlarge all distances with the same factor.
3. Let the dimensions of the large picture be a (length) by a (width)
4. Area of picture = [tex] a^{2}=192 in^{2} [/tex]
[tex]a= \sqrt{192} = \sqrt{16*12}= \sqrt{16*4*3}=4*2* \sqrt{3}=8\sqrt{3} (feet) [/tex]
Answer: the dimensions are [tex]8\sqrt{3} (feet) [/tex] by [tex]8\sqrt{3} (feet) [/tex]
