Alistarr
Alistarr
23-06-2017
Mathematics
contestada
Solve n3 + 2n2 - 15n = 0 by factoring.
Respuesta :
Floki22
Floki22
23-06-2017
n³ - 2n² - 15n = 0
"n"
n (n² + 2n - 15) = 0
n = 0
n² + 2n - 15 = 0
Δ = (2)² - 4(1)(-15)
Δ = 4 + 60 = 64
n' = (-2+8) / 2 = 6/2 =3
n'' = (-2-8) / 2 = -10/2 = -5
Solution:
S {-5 , 0 , 3 }
Answer Link
irspow
irspow
23-06-2017
n^3+2n^2-15n=0
n(n^2+2n-15)=0
n(n^2+5n-3n-15)=0
n(n(n+5)-3(n+5))=0
n(n-3)(n+5)=0
n={-5, 0, 3}
Answer Link
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