Respuesta :
Given
[tex]f(x)= \frac{1}{3} x-2[/tex]
and
[tex]g(x)= \frac{1}{3} x+3[/tex]
[tex]g(x)=f(x)+k \\ \\ \frac{1}{3} x+3=\frac{1}{3} x-2+k \\ \\ k=3+2=5[/tex]
Therefore, k = 5
[tex]f(x)= \frac{1}{3} x-2[/tex]
and
[tex]g(x)= \frac{1}{3} x+3[/tex]
[tex]g(x)=f(x)+k \\ \\ \frac{1}{3} x+3=\frac{1}{3} x-2+k \\ \\ k=3+2=5[/tex]
Therefore, k = 5