Respuesta :

mreijepatmat
Let a =107°   and b=42°;

So cos 107° cos 42° + sin 107° sin 42°  = cosa.cos42 + sina.sinb = cos(a-b)

and cos 107° cos 42° + sin 107° sin 42°  = cos(107-42) = cos(65°)

Answer: It will be

[tex]\cos65\textdegree\ and\ \sin 25\textdegree[/tex]

Step-by-step explanation:

Since we have given that

cos 107° cos 42° + sin 107° sin 42°

As we know the formula :

[tex]\cos A\cos B+\sin A\sin B=cos(A-B)[/tex]

So, applying the above formula , we get

[tex]A=107\textdegree\\B=42\textdegree[/tex]

Now, we have to write it in cosine terms,

So, we get,

[tex]\cos(107\textdegree-42\textdegree)=\cos65\textdegree[/tex]

So, in terms of cosine , it will be

[tex]\cos65\textdegree[/tex]

In terms of sine , it will be

[tex]\cos 65\textdegree=\sin(90\textdegree-65\textdegree)=\sin 25\textdegree[/tex]

Hence, it will be

[tex]\cos65\textdegree\ and\ \sin 25\textdegree[/tex]

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