Respuesta :

To factor our the following expression we proceed as follows;
p(x)=x^5-4x^3-2x^2-4x
factoring out x we get:
p(x)=x(x^4-4x^2-2x-4)
factoring further we get:
x^4-4x^2-2x-4
=(x+2)(x^3-2x^2-2)
Therefore our expression becomes:
p(x)=x(x+2)(x^3-2x^2-2)
Therefore the factors are x and (x+2) and (x^3-2x^2-2)

Answer:

The factor is : [tex]x(x+2)(x^{3}-2x^{2}-2)[/tex]

Step-by-step explanation:

Given expression is :

[tex]p(x)=x^{5}-4x^{3}-2x^{2}-4x =0[/tex]

Taking out x common factor we get

[tex]x^{4}-4x^{2}-2x-4=0[/tex]

Further applying rational root theorem we get

[tex](x+2)\frac{x^{4}-4x^{2}-2x-4}{x+2}[/tex]

Now we will divide [tex]\frac{x^{4}-4x^{2}-2x-4}{x+2}[/tex] and get

[tex]x^{3}+\frac{-2x^{3}-4x^{2}-2x-4}{x+2}[/tex]

[tex]x^{3}-2x^{2} +\frac{-2x-4}{x+2}[/tex]

[tex]\frac{-2x-4}{x+2}[/tex] = -2

The next factor becomes : [tex]x^{3}-2x^{2} -2[/tex]

Now clubbing all the factors we get the final answer:

[tex]x(x+2)(x^{3}-2x^{2}-2)[/tex]