Answer: The correct answer is Option b.
Explanation:
To calculate the number of moles, we use the equation:
[tex]text{Number of moles}=\frac{text{Given mass}}{\text{Molar mass}}[/tex] .....(1)
Given mass of oxygen = 8.94 g
Molar mass of oxygen = 32 g/mol
Putting values in above equation, we get:
[tex]\text{Moles of oxygen}=\frac{8.94g}{32g/mol}=0.28mol[/tex]
The chemical equation for the combustion of methane is given as:
[tex]CH_4+2O_2\rightarrow CO_2+2H_2O[/tex]
By Stoichiometry of the reaction:
2 moles of oxygen gas produces 1 mole of carbon dioxide.
So, 0.28 moles of oxygen gas will produce = [tex]\frac{1}{2}\times 0.28=0.14mol[/tex] of carbon dioxide gas.
Now, calculating the mass of carbon dioxide by using equation 1.
Moles of carbon dioxide = 0.14 moles
Molar mass of carbon dioxide = 44.01 g/mol
Putting values in equation 1, we get:
[tex]0.14mol=\frac{\text{Mass of carbon dioxide}}{44.01g/mol}\\\\\text{Mass of carbon dioxide}=6.15g[/tex]
Hence, the correct answer is Option b.
