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if you dissolve 0.0147 kg of glucose (c6h12o6) using 0.150 l of water with a density of 1.00 g/ml, what will be the molality?

Respuesta :

Moles of glucose = 14.7/180.15 = 0.0816moles.

Mass of solvent(water) = density of water x volume = 1 x 150 g = 150g

Mass of water in Kg = 0.15 Kg 

Molality of glucose = moles of glucose/ mass of water
                              = 0.0816 / 0.15 = 0.54 molality.

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