Respuesta :
[tex] \frac{28x^3+42x^2-35x}{7x}= \frac{7x(4x^2+6x-5)}{7x}= 4x^2+6x-5[/tex]
(28x^3 + 42x^2 - 35x) / 7x
** keep in mind, when dividing exponents, u subtract the exponents
4x^2 + 6x - 5 <==
** keep in mind, when dividing exponents, u subtract the exponents
4x^2 + 6x - 5 <==