Respuesta :
Remember SOH CAH TOA
sin=opposite/hypotenuse
cos=Adjacent/Hypotenuse
Tan=Opposite/Over Adjacent
So from the problem:
Sin=15/17
which by SOH CAH TOA means cos = x/17
because this is a right triangle you can do:
[tex] \sqrt{17^{2}-{15^{2}=x [/tex]
so cos = [tex] \sqrt{17^{2}-{15^{2}/17 [/tex]
sin=opposite/hypotenuse
cos=Adjacent/Hypotenuse
Tan=Opposite/Over Adjacent
So from the problem:
Sin=15/17
which by SOH CAH TOA means cos = x/17
because this is a right triangle you can do:
[tex] \sqrt{17^{2}-{15^{2}=x [/tex]
so cos = [tex] \sqrt{17^{2}-{15^{2}/17 [/tex]
Answer:
cos (theta) = +/- 8/17
Step-by-step explanation:
Use the definition of cosine to find the value of cos (theta)
cos (theta)=adj/hyp
Substitue in the known values
cos (theta)=+/- 8/17