At a pressure 41 kPa, the gas in a cylinder has a volume of 16 liters. Assuming temperature remains the same, if the volume of the gas is decreased to 4 liters, what is the new pressure
If temperature (T) and amount of gas (n) remain constant, but pressure (P) and volume (V) change, then the ideal gas law: PV = nRT becomes P1V1 = P2V2 --> (41)(16) = P2 (4) --> P2 (4) = 656 P2 = 656/4 = 164 kPa
