Respuesta :

KABOOMADEEBOOM
SR because any point on a perpendicular bisecting line is equidistant from the ends of the bisected segment.
calculista

Answer:

[tex]SR[/tex]

Step-by-step explanation:

In this problem we have

[tex]RX=XT[/tex] -----> given problem

[tex]XS[/tex] ---> is a common side both triangles

In the right triangle RSX

Applying the Pythagoras Theorem

[tex]SR^{2}=RX^{2}+XS^{2}[/tex] ------> equation A

In the right triangle XST

Applying the Pythagoras Theorem

[tex]ST^{2}=XT^{2}+XS^{2}[/tex] ------> equation B

remember that -----> [tex]RX=XT[/tex]

Substitute

[tex]ST^{2}=RX^{2}+XS^{2}[/tex] ------> equation C

Compare equation A and equation C

[tex]SR=ST[/tex]

Otras preguntas