Which of the following are equivalent to the function y = 4cos x - 2? a. y= 4sin(x-pi/2)-2 b. y=4sin(x+pi/2) - 2 c. y=4cos(-x)-2 d. y=-4cos x +2.

To answer this question, we must know some identities:
1. cos(x) is an even function, so cos(x)=cos(-x) [this makes choice (c) true]
2. sin(x) and cos(x) are the same periodic functions with a phase-shift of pi/2, so that sin(x+pi/2)=cos(x) [this makes choice (b) true]
3. also, sin(x) is symmetrical about pi/2, and cos(x) is symmetrical about x=0. This means that sin(x)=cos(pi/2-x) [ this case is not present in the choices ]

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pinquancaro pinquancaro · Answer 2 · 2019-06-13T06:20:28+02:00

Answer:

Option b and c is correct.

Step-by-step explanation:

Given : Function [tex]y=4\cos x-2[/tex]

To find : Which of the following are equivalent to the function?

Solution :

The function given is [tex]y=4\cos x-2[/tex]

We know that,

[tex]\cos(-x)=\cos(x)[/tex]

and [tex]\sin(\frac{\pi}{2}+x)=\cos(x)[/tex]

Applying these in the given function,

Using, [tex]\cos(-x)=\cos(x)[/tex]

[tex]y=4\cos (-x)-2[/tex]

[tex]y=4\cos (x)-2[/tex]

So option c is equivalent.

Using,[tex]\sin(\frac{\pi}{2}+x)=\cos(x)[/tex]

Substitute

[tex]y=4\sin(\frac{\pi}{2}+x)-2[/tex]

[tex]y=4\cos (x)-2[/tex]

So option b is equivalent.

Therefore, Option b and c is correct.