Answer:
ΔABP is congruent to ΔBAQ
ΔABP ≡ ΔBAQ
Explanation:
We are given two triangles; ΔABP and ΔABQ
In these two triangles, we have:
AB as a common side
∠ABP = ∠BAQ
AQ = BP
We can conclude that these two triangles are congruent by SAS (side-angle-side) postulate which states that:
"When two sides and the included angle between them in the first triangle are congruent to the corresponding two sides and the included angle between them in the second triangle, then the two triangles are congruent"
Note that when writing congruency statements, the order of the letters is critical as each angle/side in the first triangle must be congruent to its corresponding angle/side in the second triangle.
Based on the above, the congruency statement would be:
ΔABP is congruent to ΔBAQ
Hope this helps :)
