Respuesta :
5 girls, 5 boys...total of 10 students
P(1st pick is a girl) = 5/10 which reduces to 1/2
P(2nd pick is a boy) = 5/9
P (both) = 1/2 * 5/9 = 5/18 <=
P(1st pick is a girl) = 5/10 which reduces to 1/2
P(2nd pick is a boy) = 5/9
P (both) = 1/2 * 5/9 = 5/18 <=
Answer:
The required probability is 5/18.
Step-by-step explanation:
Total number of total students = 10
Number of girls = 5
Number of boys = 5
Formula for probability:
[tex]Probability=\frac{\text{Favorable outcome}}{\text{Total outcome}}[/tex]
The probability that the first student chosen will be a girl = [tex]\frac{5}{10}=\frac{1}{2}[/tex]
After selecting 1 student, the total number of student is
[tex]10-1=9[/tex]
The probability that the second student chosen will be a boy = [tex]\frac{5}{9}[/tex]
The probability that the first student chosen will be a girl and the second will be a boy is
[tex]P=\frac{1}{2}\times \frac{5}{9}[/tex]
[tex]P=\frac{5}{18}[/tex]
Therefore the required probability is 5/18.