The wavelength of a standing wave is equivalent to:
wavelength = 2 l / n
Where l is the length of
the string and n is the number of segments.
so, wavelength = 2 (0.2 m) / 5
wavelength = 0.08m (ANSWER)
Answer:
[tex]\lambda=80\ cm[/tex]
Explanation:
It is given that,
Length of the string, L = 200 cm = 2 m
Frequency, f = 120 Hz
It vibrates in 5 distinct segments such that there is fifth harmonics. For a string fixed at both ends, the wavelength is given by :
[tex]\lambda=\dfrac{2}{5}L[/tex]
[tex]\lambda=\dfrac{2}{5}\times 2[/tex]
[tex]\lambda=0.8\ m[/tex]
[tex]\lambda=80\ cm[/tex]
So, the wavelength of the string fixed at both ends is 80 cm. Hence, this is the required solution.
