if in 2000 there were 430 folksk, 2010 is 10 years later, thus t = 10
[tex]\bf \qquad \textit{Amount for Exponential Growth}\\\\
A=I(1 + r)^t\qquad
\begin{cases}
A=\textit{accumulated amount}\\
I=\textit{initial amount}\to &430\\
r=rate\to 0.9\%\to \frac{0.9}{100}\to &0.009\\
t=\textit{elapsed time}\to &10\\
\end{cases}
\\\\\\
A=430(1+0.009)^{10}\implies A=430(1.009)^{10}[/tex]
