The required moles of Mg(OH)₂ that are needed to completely neutralize 2.48 mol of HNO₃ is 1.24 moles.
Stoichiometry of the reaction gives idea about the relative amount of moles of reactants and products present in the given chemical reaction.
Given chemical reaction is:
Mg(OH)₂ + 2HNO₃ → Mg(NO₃)₂ + 2H₂O
From the stoichiometry of the reaction, it is clear that:
2 moles of HNO₃ = reacts with 1 moles of Mg(OH)₂
2.48 moles of HNO₃ = reacts with (1/2)(2.48)=1.24 moles of Mg(OH)₂
Hence required moles of Mg(OH)₂ is 1.24mol.
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